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Can someone please help me with a limit trig function?
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the limit of sin3x/xcosx as x approaches 0 is?
You have formula to do that
\(\lim_{x\rightarrow 0}\dfrac{sin (x)}{x}=1\), right?
yes
wait first of all I took the 3 out of the limit and put it in front is that ok?
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so, if x-->0 ,then 3x -->0 also, right? Now, you just multiple 3 both numerator and denominator. What do you get?
\[\lim_{x\rightarrow 0}\dfrac{3*sin(3x)}{3x*cos(x)}|dw:1473635655452:dw|\]
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