Solve for p. 3+|1+p|=12 A.p = 8 or p=−10 B.p = 14 or p=−16 C.p = 10 or p=−10 D.p = 8 or p=−8
First we need to get rid of 3 Subtract 3 on both sides |1 + p| = 9 Now we need 2 equations 1 + p = 9 1 + p = - 9 Solve for p in both
here are the steps isolate the term with the subject you need undo the modulus so you have 2 equations solve for the variable/subject always maintain the balance of an equation
Ya'know this is why PA is better because they give the answer instead of telling you how to do it WITHOUT the answer.
If you are told how to solve it, you won't have to depend on others to solve it for you.
I'm to dumb to look at that.
It's okie ^.^ You're not dumb (:
Then why'd you answer the question
Because you asked it?
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