Question

A particle moves along the x-axis with a velocity v given by v(t) = 2t^2 - t + 1. When t = 0, the particle is at x = -3. Find the position along the x axis of the particle at t = 2

A) 7
B) 7 / 3
C) 1
D) 22
E) 3 / 7

I'm 98.8% Sure its B but that 1.2% is getting to me

Answer 1

v = dx/dt


dx = 2t^2 - t + 1 dt


integrate x from (-3 to x) and t from ( 0 to t ) or (0 to 2) directly


x + 3= (2/3)t^3 - (1/2)t^2 + t - 0

x = (2/3)t^3 - (1/2)t^2 + t - 3

at t = 2

x = 7/3

Answer 2

I KNEW IT!!!! Thanks for The assist man

Answer 3

Any time.