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Can someone please explain how to do this function? See attached
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The domain is the values that I can substitute with it freely without making the Rational function is undefined (its denominator equal to zero) Therefore we can substitute with all real number except that make x^2-3x-10 equal to zero \[x^2-3x-10=0\] \[(x-5)(x+2)=0\] \[x=5 and x=-2\] So the domain will be Real numbers-{5,-2}
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