Find the DOMAIN of the function in INTERVAL NOTATION.

F(x) = cube root(5t-7)

I will post my own attempt in a sec.

Question

Find the DOMAIN of the function in INTERVAL NOTATION.


F(x) = cube root(5t-7)

I will post my own attempt in a sec.

korosh23 · Answer

$$f(x) = \sqrt[3]{5t-7}$$     ---> This is the question


My own attempt:

$$5t-7 \ge 0$$
$$t \ge 7/5$$

Domain in interval notation:
$$[7/5, +\infty )$$

zzr0ck3r · Answer

You only need to do this for even roots, cube root has all real numbers $\mathbb{R}$ as domain.

zzr0ck3r · Answer

But if that 3 were a 4, you nailed it :)

korosh23 · Answer

oh you are right . So it would be (-infinity, infinity).

zzr0ck3r · Answer

Correct

korosh23 · Answer

Thanks a lot @zzr0ck3r  :)

zzr0ck3r · Answer

This is one of those times that open study worked exactly how I would love it to always work.

One little thing led you to doing the thing you would do for the even case, so you come here and write it up, obviously not just looking for answers, and in writing it up, I almost guarantee that you will not forget it come test day. 

awesome