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Could someone please help me with this problem? I'm having trouble understanding how to do it. Find f^-1 for the function
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Just this prob, or in general what to do?
\[\large y=f(x)=(x-2)^{1/3}+8\] change y and x around, solve for y to get the inverse f^-1 \[\large x = (y-2)^{1/3}+8\]
When you graph both, they should be a reflection of each other over the line y=x
(x - 8)^3 + 2 = y = f^-1(x)
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a) subtract 8 b) cube both sides c) add 2
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