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The two functions t(x) and v(x) are defined below. t(x)=6x-1 v(x)=x^2+2 Evaluate the composition of functions v(t(4))
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@ zepdrix @zzr0ck3r
@zepdrix
v(x) = x^2 + 2 so v[ t(x)] = [t(x)]^2 + 2 = [ 6x-1]^2 + 2
i dont really understand
uh where did the 6x come frome
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@agent0smith could you help make it clearer
The 6x came from t(x)... t(x)=6x-1 v(x)=x^2+2 v[ t(x) ] = [ t(x) ]^2 + 2 = [ 6x-1 ]^2 + 2
but how about the 4
v(t(4))
v[ t(x) ] = [ 6x-1 ]^2 + 2 v[ t(4) ] means plug in x=4
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