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please help easy question
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a) recall, The average velocity is a displacement divided by a time, or in this case since velocity vs time is shown and there is a constant acceleration(straight line), the average velocity can be found from \[\large v _{ave }=\frac{ v _{1}+v _{2} }{ 2 }\]
from t=0 to t=4 seconds \[\huge v _{ave}=\frac{ v _{t=0} +v _{t=4}}{ 2 }\]
6m/s??
@DanJS
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why did you divide by 2?
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