Ask your own question, for FREE!
Physics 20 Online
OpenStudy (user123):

helpppppp

OpenStudy (user123):

OpenStudy (user123):

@zepdrix

OpenStudy (jiteshmeghwal9):

From t=0-2 sec the slope of given graph is a positive constant which means velocity is a positive constant. From t=2-3 sec the slope of position versus time graph is negative & constant which implies that velocity of object is negative & constant. From t=3-5 sec the object is at rest which means the velocity of object in this interval is zero. From t=5-6 sec the object again starts to move with a constant & positive velocity as the slope is positive & constant in this interval.

OpenStudy (jiteshmeghwal9):

From this information we may conclude that from t=0-2 sec the v-t graph is parallel & above time axis . from t=2-3 sec we may conclude that v-t graph is parallel to time axis & below the time axis. from t=3-5 sec the v-t graph coincides with the time axis. from t=5-6 sec the v-t graph is parallel & above the time axis

OpenStudy (jiteshmeghwal9):

after forming v-t graph u will see that the v-t graph is always parallel to time axis i.e; slope of v-t graph is always zero. so we may conclude that the acceleration is always zero.

OpenStudy (user123):

Do you agree to this?

OpenStudy (user123):

@jiteshmeghwal9

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!