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Solve the following system of equations by the substitution method. 10x + 10y = 1 x = y - 3 What is the value of y? -29/20 31/20 -3/2
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alright lets go step by step ;D
\[x=y-3; 10x+10y=1\]
ok
\[10x+10y=1\] \[10(y-3)+10y=1\]
\[10\times10=?\]
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10x + 10y =1 x - y = -3 (multiply by 10 ) then 10x+10y =1 10x-10y =-30 adding both new equations 20x=-29 x=-29/20 then subistute y = 31/20
please go step by step with the user so they won't be confused
it is my first hour here sorry
okk
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