In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability that the family has 0, 1, or 2 girls.
(a) Draw a tree diagram showing the possibilities for each outcome.
(b) Create the binomial distribution table for P (X).

I think I have A done but I need help on B.

Question

In a certain country, the probability that a baby that is born is a boy is 0.52 and the probably that a baby that is born is a girl is 0.48. A family has two children. If X is the number of girls born to a family, find the probability that the family has 0, 1, or 2 girls. 
(a)  Draw a tree diagram showing the possibilities for each outcome.
(b)  Create the binomial distribution table for P (X). 

I think I have A done but I need help on B.

hadeel · Answer

Prob(BB) = 0.52*0.52 = 0.2704  this is the probability that the family has 0 girl or 2 boys
Prob(BG) or Prob(GB) = 0.52*0.48  = 0.2496 + 0.2496 = 0.4992 this is the probability that the family has 1 gril 
Prob(GG) = 0.48*0.48 = 0.2304 this is the probability that the family has 2 girl 
i hope it helpful !