Question

PLZ HELP ME I WILL MEDAL IF U WANT PLZ!

Answer 1

@Nnesha @Conqueror

Answer 2

\[2s^3 -4r^2 \]

Answer 3

\[2(5)^3 - 4(1)^2\]

Answer 4

Equation: 2s^3 - 4r^2
r=1, s=5

What you want to do is substitute s = 5 and r =1 in the equation.
Wherever you see an s in the equation erase it and put parentheses ( ), inside the parentheses put the number 5 in it
2*(5)^3-4r^2

Just do the same for r too

Answer 5

\[2(125) - 4\]

Answer 6

\[250 - 4\]

Answer 7

\[246\]

Answer 8

where did you get the 125?

Answer 9

\[5^3 = 5 \times 5 \times 5\]

Answer 10

\[5 \times 5 \times 5 = 25 \times 5 = 125\]

Answer 11

ohh

Answer 12

Do you understand how to set it up?

Answer 13

what about the 250 and 246?

Answer 14

here is what I have so far @ShadowLegendX

Answer 15

hmm, why do you have that last line there, 5 times 5 times 5 = 25 times 5 = 125

Answer 16

Do you have to show how you got 125?

Answer 17

well I just wanted to put it there.

Answer 18

Ok, that's alright, keep going

Answer 19

so then what do I do next?

Answer 20

Tell me where you're at

Answer 21

well like an the attachment I put here I am where I put 2(125) - 4

Answer 22

*on

Answer 23

So, following PEMDAS, what do we do next?

Answer 24

divide

Answer 25

What are we dividing, and by what?

Answer 26

125 divided by 5?

Answer 27

Why would you divide 125 by 5?

Answer 28

because s = 5?

Answer 29

But where in the expression, does it have the division sign

Answer 30

idk

Answer 31

Well, what does \[2(125) \] mean?

Answer 32

divide?

Answer 33

or multiply cause dont parentheses multiply?

Answer 34

Yes

Answer 35

2(2) = 4

2 times 2 = 4

3(3) = 9

3 times 3 = 9

4(5) = 20

4 times 5 = 20

Answer 36

So

\[2(125) - 4\]

Answer 37

What do we do first, following PEMDAS?

Answer 38

Parentheses, Exponents, Multiply, Divide, Add, Subtract

Answer 39

We multiply

Answer 40

2 times 125 = ?

Answer 41

2 * 125 = 250

Answer 42

??hello

Answer 43

Correct

Answer 44

\[250 - 4 = ?\]

Answer 45

246

Answer 46

k thx im just gonna leave it like this :) thx again

Answer 47

No problem

Answer 48

Glad I could assist you