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Use the square root method to find the solutions to 3x^2+2=0
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Can someone tell me where I'm going wrong: \[3x^2+2=0\] \[3x^2=-2\] \[x^2=-2/3\] \[\sqrt{x^2}=\sqrt{-2/3}\] \[x=+-i \sqrt{2/3}\]
everything is correct but the last one is positive...
The answer in the book says it should be \[+-i \sqrt{6}/3\]
hmm...
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