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Evaluate 8^-4/3
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\[8^{-4/3}\]
\[8 = 2^3\] u can proceed now
I'm not sure how to apply that to the question
\[8^{-\frac{ 4 }{ 3 }} = (2^3)^{-\frac{ 4 }{ 3 }}\] now??
I'm not sure what to do with the ^-4/3 part
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\[(a^x)^y = a^{xy}\]
Sorry, I'm still confused
see as \[(a^x)^y = a^{xy}\] \[(2^3)^{-4/3}\] \[2^{3 \times (-4/3)}\] \[2^{-4}\]
Ah okay, and then 2^-4 = 1/16
yeah... :)
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Okay thanks for all your help!
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