Please help quickly! I'm horrible at this part of geometry In the figure below, segment CD is parallel to segment EF and point H bisects segment DE: The figure shows a polygon comprised of four triangles, AIC, DIH, HEG, and FGB. Prove ΔDIH ≅ ΔEGH (Attachment below!)
@jhonyy9 could you help on this?
I saw you were looking at the other question and thought you might be able to help? Sorry if its random
ok like a first think than you check this figure posted you see that the opposite angles of H are congruent yes ?
Mhm?
given that CD parallel EF so from this result that two parallels intersected by a line create congruent angles so angle D congruent angle E
given again that H bisect segment DE so from this result that DH congruent HE so from ASA similarity theorem result triangle DIH similar triangle HGE hope helped
Yes absolutely! Thank you very much sir!
np anytime was my pleasure good luck bye bye
hope you understand it easy sure yes ?
Yes! i understand much better now, I really appreciate your help!
ok bye bye
and anytime just tag me - ok. ? i will try help you
Okay! Thank you very much, I'll remember that!
Have a wonderful day!
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