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Mathematics 12 Online
OpenStudy (kevin):

Defined N! = N x (N-1) x .. x 2 x 1 and N # = N + (N-1) + ... + 2 + 1 Example: 4! = 4 x 3 x 2 x 1 = 24 4 # = 4 + 3 + 2 + 1 = 10 What is the last digit of ((5 #) #) + ((3 #) #) - ((5!)! + (3!)!)?

OpenStudy (kevin):

@mathmate @FaiqRaees

OpenStudy (faiqraees):

Well that's a heck of a calculation

OpenStudy (unavailabilityy):

Lol

OpenStudy (kevin):

That's the question

OpenStudy (faiqraees):

Are you allowed to use a calculator?

OpenStudy (kevin):

You need to find the last digit of ((5 #) #) + ((3 #) #) - ((5!)! + (3!)!)

OpenStudy (kevin):

It just about pattern. We must solve it the easiest way without calculator

OpenStudy (kevin):

! is factorial # is summation @FaiqRaees

OpenStudy (faiqraees):

I am pretty much aware of that

OpenStudy (kevin):

Owhh... I got it

OpenStudy (kevin):

Thx guys and Una :D

OpenStudy (brainzonly):

:D I love these

OpenStudy (kevin):

@brainzonly lol I still have many question, don't worry

OpenStudy (brainzonly):

yay

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