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Statistics 11 Online
OpenStudy (jcreamer):

The standard deviation for the sample consisting of 83, 21, and 65 is I don't understand what they are asking for??

OpenStudy (danieldjpon3):

1. Work out the Mean (the simple average of the numbers) 2. Then for each number: subtract the Mean and square the result 3. Then work out the mean of those squared differences. 4. Take the square root of that and we are done!

OpenStudy (danieldjpon3):

So add teh numbers and then divide them by 3

OpenStudy (danieldjpon3):

the*

OpenStudy (danieldjpon3):

169 divided by 3

OpenStudy (welshfella):

the standard deviation gives a measure of the spread of data around the mean

OpenStudy (danieldjpon3):

we get 56 if rounded to the nearest whole number

OpenStudy (danieldjpon3):

And you do the rest

OpenStudy (danieldjpon3):

just follow the steps

OpenStudy (jcreamer):

Thank you so much!!! I was making that way too hard..

OpenStudy (danieldjpon3):

ye

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