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Mathematics 20 Online
OpenStudy (raffle_snaffle):

Determine the equations of motion for constant jerk. An object's position is described by the following polynomial for 0 to 10 s. x = t3 − 15t2 + 54t Where x is in meters, t is in seconds, and positive is forward. Determine… the object's velocity as a function of time the object's acceleration as a function of time the object's maximum velocity the object's minimum velocity the time when the object was moving backward the times when the object returned to its starting position the object's average velocity the object's average speed

OpenStudy (raffle_snaffle):

@Will.H help me please.

OpenStudy (raffle_snaffle):

FREE MEDAL!

OpenStudy (will.h):

the object velocity as a function of time now i know that it is \[x = t^3 - 15t^2 + 54t\] what is x and what is t? is x the velocity?

OpenStudy (raffle_snaffle):

first derivative is V, second derivative is acceleration.

OpenStudy (raffle_snaffle):

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