Question

Determine the equations of motion for constant jerk.
An object's position is described by the following polynomial for 0 to 10 s.
x = t3 − 15t2 + 54t

Where x is in meters, t is in seconds, and positive is forward. Determine…

the object's velocity as a function of time
the object's acceleration as a function of time
the object's maximum velocity
the object's minimum velocity
the time when the object was moving backward
the times when the object returned to its starting position
the object's average velocity
the object's average speed

Answer 1

@Will.H help me please.

Answer 2

FREE MEDAL!

Answer 3

the object velocity as a function of time now i know that it is
\[x = t^3 - 15t^2 + 54t\]
what is x and what is t?
is x the velocity?

Answer 4

first derivative is V, second derivative is acceleration.