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OpenStudy (danieldjpon3):
Hardest Question EVER!!!! Medal If Answered.
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OpenStudy (danieldjpon3):
If x, y, and z are positives integers and 3x = 4y = 7z, then the least possible value of x + y+ z is.. (A) 33 (B) 40 (C) 49 (D) 61 (E) 84
OpenStudy (danieldjpon3):
@agent0smith @satellite73
OpenStudy (thefurball):
the least common multiple is 3*4*7 So, 3*4*7=3x=4y=7z
OpenStudy (danieldjpon3):
hmm
OpenStudy (danieldjpon3):
I don't get it :P
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OpenStudy (thefurball):
You can solve that equation to get x=28,y=21, and z=12 28+21+12=61
OpenStudy (danieldjpon3):
hmmm
OpenStudy (danieldjpon3):
Ugh hmmm
OpenStudy (danieldjpon3):
So what's the answer?
OpenStudy (danieldjpon3):
Oh the answer is 61 Oh ok Thank you
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OpenStudy (danieldjpon3):
I have one more
OpenStudy (danieldjpon3):
OpenStudy (danieldjpon3):
What's the answer
OpenStudy (danieldjpon3):
@agent0smith and @thefurball and @satellite73 pls
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