Question

Hardest Question EVER!!!! Medal If Answered.

Answer 1

If x, y, and z are positives integers and 3x = 4y = 7z, then the least possible value of x + y+ z is..
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84

Answer 2

@agent0smith @satellite73

Answer 3

the least common multiple is 3*4*7
So, 3*4*7=3x=4y=7z

Answer 4

hmm

Answer 5

I don't get it :P

Answer 6

You can solve that equation to get
x=28,y=21, and z=12
28+21+12=61

Answer 7

hmmm

Answer 8

Ugh hmmm

Answer 9

So what's the answer?

Answer 10

Oh the answer is 61 Oh ok Thank you

Answer 11

I have one more

Answer 12

https://blog.prepscholar.com/hs-fs/hubfs/body_question1-1.jpg?t=1474052783303&width=320&name=body_question1-1.jpg

Answer 13

What's the answer

Answer 14

@agent0smith and @thefurball and @satellite73 pls