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Mathematics 21 Online
OpenStudy (danieldjpon3):

Hardest Question EVER!!!! Medal If Answered.

OpenStudy (danieldjpon3):

If x, y, and z are positives integers and 3x = 4y = 7z, then the least possible value of x + y+ z is.. (A) 33 (B) 40 (C) 49 (D) 61 (E) 84

OpenStudy (danieldjpon3):

@agent0smith @satellite73

OpenStudy (thefurball):

the least common multiple is 3*4*7 So, 3*4*7=3x=4y=7z

OpenStudy (danieldjpon3):

hmm

OpenStudy (danieldjpon3):

I don't get it :P

OpenStudy (thefurball):

You can solve that equation to get x=28,y=21, and z=12 28+21+12=61

OpenStudy (danieldjpon3):

hmmm

OpenStudy (danieldjpon3):

Ugh hmmm

OpenStudy (danieldjpon3):

So what's the answer?

OpenStudy (danieldjpon3):

Oh the answer is 61 Oh ok Thank you

OpenStudy (danieldjpon3):

I have one more

OpenStudy (danieldjpon3):

What's the answer

OpenStudy (danieldjpon3):

@agent0smith and @thefurball and @satellite73 pls

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