Question

Precalculus help needed!
The function f(x)=(x+8)^2-1 is not one-to-one. Identify a restricted domain that makes the function one to one, and find the inverse function.

Answer 1

Find the axis of symmetry (which is the x coordinate of the vertex). You can use that to restrict the domain.

Answer 2

Could you explain? (Sorry my brain is exhausted from work)

Answer 3

A function like\[\large f(x)=(x-h)^2+k\]has a vertex (h, k).

You could restrict its domain to x>h or x<h, either would work.