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OpenStudy (mindblast3r):
@study_buddy99
OpenStudy (study_buddy99):
what is it?
OpenStudy (mindblast3r):
let me write the question one sec.
OpenStudy (mindblast3r):
The expedition team plan a final practice run to test the range of their communication equipment. One member travels a distance of 12 km due north. Another team member heads 50° east of north and travels a distance of 10 km. How far apart are the two team members? Round your answer to the nearest tenth of a kilometer.
OpenStudy (mindblast3r):
is that how you would draw the triangle? I'm not sure
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OpenStudy (mindblast3r):
|dw:1474258825845:dw|
OpenStudy (mindblast3r):
you know the consine law right?
OpenStudy (mindblast3r):
cosine*
OpenStudy (study_buddy99):
I ned to go look at my notes really quick
OpenStudy (mindblast3r):
I can tell you the formula if you want
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OpenStudy (mindblast3r):
The answer is 9.5 km
OpenStudy (study_buddy99):
okay... yeah what's the formula?
OpenStudy (mindblast3r):
I don't know, I'm not getting the correct answer though... so I don't know
OpenStudy (mindblast3r):
I don't know if i'm even drawing the correct triangle
OpenStudy (mindblast3r):
sec
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OpenStudy (mindblast3r):
\[a^2=b ^{2}+c^{2}-2bc \times \cos A\]
OpenStudy (jiteshmeghwal9):
\[cos50^0= \frac{12^2+10^2+x^2}{2*12*10} \]
OpenStudy (jiteshmeghwal9):
Solve for x
OpenStudy (mindblast3r):
Did I draw the triangle correctly though?
OpenStudy (mindblast3r):
@jiteshmeghwal9
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OpenStudy (mindblast3r):
ohhhhhhhhhhhh, it makes sense now!!
OpenStudy (mindblast3r):
Just not sure if i drew the triangle correctly though
OpenStudy (jiteshmeghwal9):
U drew the triangle correctly
OpenStudy (mindblast3r):
you sure? I think it's like this
OpenStudy (mindblast3r):
|dw:1474259633700:dw|
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