Question

(1+cotA+tanA)(sinA-cosA)=secA/sec^2A-cosecA/sce^2A

Answer 1

\(\color{black}{\displaystyle \left(1+\cot A + \tan A\right)\left(\sin A - \cos A\right)=\frac{\sec A}{\sec^2A}-\frac{\csc A}{\csc^2A}}\)

like this?

Answer 2

or like that?

\(\color{black}{\displaystyle \left(1+\cot A + \tan A\right)\left(\sin A - \cos A\right)=\frac{\sec A}{\sec^2A}-\frac{\csc A}{\sec^2A}}\)

Answer 3

(I'm just trying to make sure my interpretation of the equation is correct, before we go ahead and work it out ... Are you there?)

Answer 4

i think the second have wrote it right ?