Question

prove that :
(2n)! = (1x3x5x.......(2n-1)x2^n x(n)!

Answer 1

\[2n!=2n(2n-1)(2n-2)(2n-3)...3.2.1=1.3.5...(2n-1).2^n[n(n-1)(n-2)...3.2.1]\]
\[=1.3.5...(2n-1) .2^n.n!\]

Answer 2

i write missing part again.
\[2^n[n.(n-1).(n-2)...3.2.1]\]
=

Answer 3

Thank you , sshayer .and i am sorry for wasting your time

Answer 4

no problem.