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Can someone please explain this to me. See attached
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\[h(-3)=(-3)^2-5\times (-3)+6\] i.e. where you see an \(s\) put a \(-3\) then arithmetic
@satellite73 how would you write it in the (x,y)?
the first coordinate is \(-3\) the second is what you get
so it would be \[(-3,h(-3))\] but you still need \(h(-3)\) let me know what you get
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