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When the fraction below is written as a decimal, how many digits are in the smallest sequence of repeating digits? 41/333 A. 1 B. 2 C. 3 D. 4
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41 ÷ 333 0.123123123123
Alright so you found the decimal, now what do you think the question is asking?
how many digits are in the smallest sequence of repeating digits?
this make no sense
So your decimal is .123123123123123123, so how many digits do you see before it repeats itself?
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123
Yes, I believe the answer would be 3 digits, since 123 is constantly repeated.
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