Question

HELP!!!!

Answer 1

\[cosec \theta=\csc \theta=\frac{ 1 }{ \sin \theta }=\frac{ 3 }{ 2 }\]

so that
\[\sin \theta=\frac{ 2 }{ 3 }\]

Answer 2

You seem that you are not here.

Answer 3

find the third length by "Pathygorean theorem"
\[3^2=x^2+2^2\]
\[x=\sqrt{9-4}=\sqrt{5}\]

Answer 4

so is it C???

Answer 5

im here thx for helping me dude u are precious

Answer 6

Finally you can find the cosine of the angle by:
\[\cos \Theta=\frac{ \sqrt{5} }{ 3 }\]
But with negative sign because the angle is in the second quadrant.
so x is logically negative.

Answer 7

\[\cos \theta=\frac{ -\sqrt{5} }{ 3 }\]

choice C