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Find an equation for the tangent to the graph of f at the point P(2, f(2)) when ...
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\[f(x)=\frac{ 5 }{ 1-3x }\]
\(f'(x) \) = ??
\[f'(x)=\frac{ 15 }{ 9x^2-6x+1 }\]
y
Is that right? I used the quotient rule lol
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I didn't know how else to find it besides that
yes it is right so next bit
(2 , -1)
Okay cool. Then I plugged in 2 and got 3/5 so is that the slope?
think so
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Okay so then would I just plug in f(2) which equals -1 for y then 3/5 for the slope, 2 for x and solve for b??
sure
Okay thank you so much you actually helped a ton xD
tu
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