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What is the solution to the compound inequality 3x − 8 ≤ −5 or 2x − 7 > 5? A. X < 1 or X > 6 B. 1 ≤ X <6 C. X ≤ 1 or x > 6 D. 1 ≤ X ≤ 6
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die
Let's look at each one separately, you must solve for x.\[3x − 8 ≤ −5 \]\[3x \le 3\] What is x of the first one? Second;\[2x − 7 > 5\]\[2x > 12\] What is x for the second?
die
x=6 ?
Yes, x=6 for the second, what about the first?
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its 1
Yep, so we have \[x \le 1 \] or \[x > 6\]
thank you so much!
Yep :)
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