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A ball is thrown horizontally of a cliff. If the initial speed of the ball is 23 m/s and the cliff is 43 m high, how far from the base of the cliff will the ball land in the water below? Calculate the answer in meters (m) and rounded to three significant figures.
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Although you may be better off asking this in physics, my two cents are to use \[\Delta x=v_it+.5at^2 \] \[ v_f=v_i+at\] and \[v_f^2=v_i^2+2ax\] Solve the system and be done
wait, I have to use all three? @FibonacciChick666
uhm, well, I would since I can't remember if free fall and having an initial velocity makes a time difference
ahh, I need help :(
please!
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