Last year, the number of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.

a) on what % of the days last year did the factory produce 20,555 or fewer?
b) On what % of the days last year did the factory produce 20,610 skateboards or more?
c) On what % of the days last year did the factory produce 20, 445 skateboards or fewer?

I know this is out of policy but is it okay if u could just give the answers? I am in a bit of a hurry...I need to turn in the work today by midnight and I still

Question

Last year, the number of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.

a) on what % of the days last year did the factory produce 20,555 or fewer?
b) On what % of the days last year did the factory produce 20,610 skateboards or more?
c) On what % of the days last year did the factory produce 20, 445 skateboards or fewer?

I know this is out of policy but is it okay if u could just give the answers? I am in a bit of a hurry...I need to turn in the work today by midnight and I still

goldandpinkiscool · Answer

to do 1 more problem.... @Benji @agent0smith

benji · Answer

Ok let's see

agent0smith · Answer

First find the z score = (score - mean)/st. dev
For a) score is 20,555

goldandpinkiscool · Answer

that is all there is to it?

agent0smith · Answer

No, then you need to find the probability from a z score table.

goldandpinkiscool · Answer

Oh okay, I got it now. Thanks :D