Question

is this correcto?

Answer 1

let me draw..

Answer 2

zzzzz

Answer 3

ahh
radius is 2-x
and the height is the function right ?
and because slices are parallel to the x=2 i'm integrating with respect to x
so \[\int\limits_{ }^{} 2 \pi~ r~h~ dx \]
\[\int\limits_{0}^{4} 2 \pi~(2-x)(x^2) dx \]