Question

2x^2-27x-80=0

Answer 1

To find the solutions?

Answer 2

if yes then use the famous Quadratic formula
\[\frac{ -b \pm \sqrt{b^2 -4ac}}{ 2a }\]

Answer 3

:)

Answer 4

Here's a clue:
a = 2
b = -27
c = -80
\[\frac{-(-27) \pm \sqrt{(-27)^ {2}- 4(2)(-80)}}{ 2(2) }\]