Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (notamathgenius):

2x + 7 > x + 17 solve

OpenStudy (dmezzullo):

Get the same things on the same side

OpenStudy (will.h):

just like when you solve for an equation 1st step is to subtract x from both sides to get the X's on one side

OpenStudy (notamathgenius):

Thats where I am confused, I dont see an = sign and i forget after that

OpenStudy (dmezzullo):

the > is the same thing as an equal sign in this case

OpenStudy (helpz-q):

Lets see here

OpenStudy (will.h):

we don't need = sign because this is not equation this is inequality but treat the > as if it was equal sign

OpenStudy (dmezzullo):

So do subtract x to the left side and subtract 7 to the right

OpenStudy (notamathgenius):

\[x>10\]

OpenStudy (dmezzullo):

Correct

OpenStudy (helpz-q):

Do you have any listed values for the exponents?

OpenStudy (notamathgenius):

THANKS GUYS

OpenStudy (will.h):

2x + 7 > x + 17 Subtract x from both sides to get X's on one side 2x - x + 7 > 17 x + 7 > 17 now subtract 7 from both sides to isolate x x > 17 - 7 x > 10 make sense?

OpenStudy (will.h):

yw bye

OpenStudy (notamathgenius):

Yes, I have one more question just so i can find out an easier way on myself, 9y -5 < 8y -2

OpenStudy (will.h):

Solve it and i will check your answer.

OpenStudy (notamathgenius):

I want to say 1y -5 < 2 but i feel its wrong

OpenStudy (will.h):

it is not 2 it is -2 the sign are very important and you are right so far but just instead of 1y keep it as y

OpenStudy (will.h):

so it is y - 5 < -2 so far

OpenStudy (notamathgenius):

Now get y by itself?

OpenStudy (will.h):

Correct how do we do that?

OpenStudy (notamathgenius):

+5 on the right side which is 3 y < 3

OpenStudy (will.h):

Correct! :)

OpenStudy (notamathgenius):

Awesome i got it right do oyu want to help with a few more? You dont have too i have 10 minutes of class left

OpenStudy (will.h):

sure but i would ask you to create new post

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!