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The excursion boat on the river takes 2½ hours to make the trip to a point 12 miles upstream and to return. If the rate at which the boat travels in still water is 5 times the rate of the river current, what is the rate of the current?
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@Will.H
so the time for the river is 2.5 hours for 12 miles upstream you want to find the time if it travels in water? knowing that it would be 5 times the rate of the river correct?
It wants the rate of the current :3
It's okay, I figured it out. And I have to go, thanks!
Good job :)
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