A toy rocket is launched from a platform 42 feet above the ground at a speed of 91 feet per second. The height of the rocket in feet is given by the polynomial −16t^2 + 91t + 42, where t is the time in seconds. How high will the rocket be after 3 seconds?
2619 feet
171 feet
129 feet
267 feet

Question

danjs · Answer

The height at any time t is given as-

h(t) = -16*t^2 + 91*t + 42

The height after t=3 seconds is , h(3)