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Calculus! Please help f(x) = sqrt x+9; g(x) = 8x – 13 Find f(g(x)).
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Doesn't look like calc to me.
It's from my calculus class
Plug in 8x - 13 for 'x' in the first function. \(\sf \sqrt{8x - 13 + 9}\) Can you simplify it?
Okay! like this? sqrt 8(8x-13)+9?
sqrt 64x-95
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oh wait no
2 sqrt 2x - 1
No, combine like terms first
-13 + 9 = ?
-4
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Yes..that leaves us with: \(\sf \sqrt{8x - 4}\)
Okay thank you so much!
Yw
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