Question

http://prnt.sc/clldae
@mehek14

Answer 1

Your first problem is correct :) Though your wrong about the second one...

\(\huge{x^{2}=10}\) Since x is squared and we need to find x we would do the opposite...so we find the square root of 10 and the square root of x squared is canceled to only `x`.

\(\huge{x=\sqrt{10}}\)

Now we leave it at just that....though the sqrt of 10 can be a positive or negative...

Answer 2

thank you

Answer 3

np :)

Answer 4

could you help with another one please?