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2x + 4y = 12 y = x – 3 What is the solution to the system of equations? (–1, 8) (8, –1)
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2x+4y=12 divide both sides by 2 and will get x+2y=6 y=x-3 => x-y = 3 x+2y=6 subtract second from first equation x-y=3 ------------ 0 3y = 3 y= 3/3 = 1 y = 1 1=x-3 x = 4 y=1 but this is interesting bc. (4,1) not is there between this choices
and than you check these given choices so these not are true ,right than you substitute these value of x and y in place of x and y inside equations
but substituted 4 and 1 will get it correct sure please try,check these
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