Urgent Help!!!
hi
\[(3n^5+13n^4+8n^3-42n^2-n+18)/(3n-2)\]
I need help with Division Polynomials
can i trying help you
(3n5+13n4+8n3−42n2−n+18)/(3n−2) ok. so long division will be accepted ?
yes
the 3n you need multiplie by what to get 3n^5
no ok, i will tel you this so by n^4 bc 3n*n^4 = 3n^5 yes ?
alright
sorry (3n5+13n4+8n3−42n2−n+18)/(3n−2) = n^4 3n^5 -2n^4 ------------ subtract second from the first 0 15n^4 +8n^3 so now you need multiplie the 3n by what to get 15n^4 ?
shaleiah please collaborate
15/3 = ?
5
yes n^4 ---- = ? n
2
n on exponent 4 divide by n = ?
you need getting n on what power ?
i'm not sure
n^4 --- = n^4 *n^(-1) = n^(4-1) = n^? n
3
4-1 yes so will be n^3 but above you get an 5 what mean that 3n*5n^3 = 15n^4
(3n5+13n4+8n3−42n2−n+18)/(3n−2) = n^4 + ? 3n^5 -2n^4 ------------ subtract second from the first 0 15n^4 +8n^3 so now you need multiplie the 3n by what to get 15n^4 ?
on place of ? what you need writing there ?
5n^3
@jhonyy9
(3n5+13n4+8n3−42n2−n+18)/(3n−2) = n^4 + 5n^3 3n^5 -2n^4 ------------ subtract second from the first 0 15n^4 +8n^3 so now you need multiplie the 3n by what to get 15n^4 ? 15n^4 -10n^3 ---------------- 0 18n^3 -42n^2 so now with what you need multiplie the 3n to get 18n^3 ?
12n
@jhonyy9
why or how ? 18/3 = 12 ?
Ah, 6
(3n5+13n4+8n3−42n2−n+18)/(3n−2) = n^4 + 5n^3 +6n^2 3n^5 -2n^4 ------------ subtract second from the first 0 15n^4 +8n^3 so now you need multiplie the 3n by what to get 15n^4 ? 15n^4 -10n^3 ---------------- 0 18n^3 -42n^2 so now with what you need multiplie the 3n to get 18n^3 ? 18n^3 -12n^2 ---------------- 0 30n^2 -n and now you need multiplie the 3n to get 30n^2 by ?
10
Join our real-time social learning platform and learn together with your friends!