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Calculus! Find the coordinates of the points on the curve where the tangents are vertical.
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\[x^2-xy+y^2=9\]
\[\frac{ dy }{ dx }=\frac{ y-2x }{ 2y-x }\]
Do you mean by tangent is the first derivative?
No i found the derivative before. I gotta find the tangent line where its vertical of the first equation, if thats what you're asking.
So how can I help you,sister?
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How do I find the y or x value when the slope is undefined..?
what is the slope of a vertical line?
it is 1/0
the first derivative (or slope of tangent) is undefined. for that, denominator will be = 0 2y -x = 0
yes
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Yeah i got to that but then what? Solve for y then plug that in for y?
yes x =2y plug that in x^2−xy+y^2=9
Ahh thank you so much <3
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