Question

Find the value of the following expression:

(3^8 * 2^-5*9^0)^-2 * (2^-2/3^3)^4 * 3^28

I have my answer, but I need someone to check over it and help me on the last part, '3^28'

Answer 1

1: Simplify all of the expressions, starting from left, to right.

A: (3^8 x 2^-5 x 9^0)^-2

1A* 1: 3 x itself 8 times is 6,561

2A* We simply turn 2^-5, to 1/2^5. '2^5' is 32. (We did 2 x 2 x 2 x 2 x 2.) 1/32 is 0.03125.

3A* 9^0 is 1.

4A* 6,561 x 0.03125 (Ignoring the one, since we know it doesn't effect the problem.) = 205.03125.

205.03125^2 = 42037.8134766

1/42037.8134766 = 0.0000237881


B: So far, we replaced (3^8 x 2^-5 x 9^0)^-2 with 0.0000237881. Now we need to find out ( 2^-2/3^3.)


1B: 2^ (-2 x 4)
----------
3^ (3 x 4).

2B: 2^-8
-----------
3^12

3B: 1
------------

2^8 * 3^12


4B: Answer: 2075.94140625


C: So far we have 0.0000237881 x 2075.94140625. Now we need 3^28

Answer 2

This is my steps, can you check if what I got was right? Also, how do I find 3^28?

@Loser66

Answer 3

@ShadowLegendX

@.Sam.

@Astrophysics

Answer 4

I need latex to read it. I can't read it.

Answer 5

4 the answer is 4

Answer 6

Its simply:

Answer 7

idk

Answer 8

@loser66

Answer 9

you might be right

Answer 10

So far I have 0.000237881 x 2075.94140625 x (I don't know how to simplify 3^28)

Answer 11

@mathmate

Answer 12

This is what I need to simplify, I don't know how to simplify 3^28.