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Mathematics 8 Online
NvidiaIntely (nvidiaintely):

@Kevin I need help?

OpenStudy (kevin):

I'm here :)

NvidiaIntely (nvidiaintely):

NvidiaIntely (nvidiaintely):

How do I find the length?

NvidiaIntely (nvidiaintely):

Is it 8?

OpenStudy (kevin):

KL^2 = LJ^2 - KJ^2

OpenStudy (kevin):

sqrt(12^2 - 4^2) = 8sqrt(2)

NvidiaIntely (nvidiaintely):

Thanks!

OpenStudy (kevin):

yw :)

NvidiaIntely (nvidiaintely):

So its 8 right?

OpenStudy (kevin):

no :/

OpenStudy (kevin):

\[8\sqrt{2}\]

NvidiaIntely (nvidiaintely):

oh yeah :) Thanks!

OpenStudy (kevin):

u're welcome :)

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