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Mathematics 10 Online
OpenStudy (user123):

derivative problem

OpenStudy (user123):

OpenStudy (phi):

ok, it looks like the average velocity is 20/5 or 4 cm/sec now we need an expression for the instantaneous velocity that means we need to take the derivative (with respect to time "t") of t^2 - t+10 can you do that ?

OpenStudy (user123):

2T-1

OpenStudy (user123):

What exactly does "repect to the time of" mean

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