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The equation of the line tangent to the curve y=(kx+8)/(k+x) at x=-2 is y=x+4. What is the value of k?
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the tangent to a curve has the same slope at that point
x = -2 not 2
\[dy \over dx \] at x=-2 is equal to 1
why did you delete?
Statement was wrong
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I wrote dy/dx equal to y=x+4
So I would find y when x =-2 using the equation of the line tangent, then use those x and y values to solve for k in the equation of the curve?
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