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Mathematics 19 Online
OpenStudy (1davey29):

The equation of the line tangent to the curve y=(kx+8)/(k+x) at x=-2 is y=x+4. What is the value of k?

OpenStudy (triciaal):

the tangent to a curve has the same slope at that point

OpenStudy (triciaal):

x = -2 not 2

OpenStudy (jiteshmeghwal9):

\[dy \over dx \] at x=-2 is equal to 1

OpenStudy (triciaal):

why did you delete?

OpenStudy (jiteshmeghwal9):

Statement was wrong

OpenStudy (jiteshmeghwal9):

I wrote dy/dx equal to y=x+4

OpenStudy (1davey29):

So I would find y when x =-2 using the equation of the line tangent, then use those x and y values to solve for k in the equation of the curve?

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