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Mathematics 11 Online
NvidiaIntely (nvidiaintely):

HEEELPLE!

NvidiaIntely (nvidiaintely):

NvidiaIntely (nvidiaintely):

@OtherWorldly @jackthegreatest

OpenStudy (jiteshmeghwal9):

\[Cos B = \frac{a^2 +c^2-b^2}{2ac}\]

OpenStudy (jiteshmeghwal9):

\[Cos 41 = {(13)^2 + (12)^2 - b^2 \over 2(13)(12)}\]

OpenStudy (jiteshmeghwal9):

can u find b^2 ?

OpenStudy (jiteshmeghwal9):

\[2(12)(13)\cos 41 = (13)^2+(12)^2-b^2\]

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