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@OtherWorldly @jackthegreatest
\[Cos B = \frac{a^2 +c^2-b^2}{2ac}\]
\[Cos 41 = {(13)^2 + (12)^2 - b^2 \over 2(13)(12)}\]
can u find b^2 ?
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\[2(12)(13)\cos 41 = (13)^2+(12)^2-b^2\]
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