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@KEvin
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The base of a pyramid is a square with dimensions 12 in by 12 in. The height of the pyramid is 10 in. What is the slant height of the pyramid?
sqrt(10^2 + 6^2) = 2 sqrt(34) = 11.66
you use the pythagoreom therom becuase you know that 10 is the height and if you draw a triangle connecting the height line and the slant line the newly drawn line is 6,becasue tehs quare was 12*12 and you divide 12 by 2 so your finding the hyptoneuse to find the slant height and 6squared + 10 squared=136 and you square 136 to get 11.66,
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