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Thanks in advance! Suppose the velocity of a particle moving along the x axis varies in time according to the expression vx = (5.5 + 4.0t + 6.0t2) where t is in seconds. (b) Determine the acceleration at t = 10.0 s.
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differentiate \[v=6t^2+4t+5.5\]with respect to time & then replace t by 10 in the new expression
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