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A shipment of marbles with a mean diameter of 27 mm and a standard deviation of 0.15 mm is normally distributed. By how many standard deviations does a marble with a diameter of 26.85 mm differ from the mean?
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Calculate the "z-score."\[z=\frac{ x-\mu }{ \sigma }\]
or note that 26.85 is equal to 27.00-0.15.
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