Question

Solve for x. sin^-1(1-3x)=-pi/6

Answer 1

\(\color{black}{\displaystyle \sin^{-1}(1-3x)=-\pi/6 }\)
\(\color{black}{\displaystyle \sin^{}(-\pi/6)=1-3x }\)
\(\color{black}{\displaystyle -\sin^{}(\pi/6)=1-3x }\)
\(\color{black}{\displaystyle -\sin^{}(30^\circ)=1-3x }\)
\(\color{black}{\displaystyle -\sin^{}(30^\circ)-1=-3x }\)
\(\color{black}{\displaystyle (-\sin^{}(30^\circ)-1)\div (-3)=x }\)

Answer 2

just follow the basic steps ...