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How many multiples of 5 are there between 199 and 1,198? Hint: an = a1 + d(n − 1), where a1 is the first term and d is the common difference.
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yes this is an arithmetic series where common difference is 5 The first term here would be 200 as its the next number after 199 divisible by 5
I get stuck at an=205+5n, I don't know if I'm doing the right steps
sorry i got cut off. The equation is 1195 = 200 + (n - 1)d find n This will give you the answer
1195=200+(n-1)*5 therefore 995=(n-1)*5 i.e. n-1=995/5 =199 i.e. n=199+1=200
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